Questions 31 to 40
31.
|
The gray code of a given binary number 1001 is
| ||||||||||
Which of the following representation requires the least number of bits to store the number +255?
| |||||||||||
For two variables, n=2 , the number of possible Boolean functions is
| |||||||||||
The one major advantage of CMOS is its,
| |||||||||||
64K memory contains how many words of 8 bits each?
| |||||||||||
The simplest way to determine cache locations in which to store memory blocks is the,
| |||||||||||
The sum of -6 and -13 using 2’s complement addition is,
| |||||||||||
Which one of the following CPU registers holds the address of the instructions (instructions in the program stored in memory) to be executed next?
| |||||||||||
What are the major components of a CPU?
| |||||||||||
Given the characteristic table of a JK flip-flop, find the missing output value.
J K Q(t+1)
0 0 Q(t)
0 1 0
1 0 1
1 1 ---
|
Answers
31.
|
Answer : (c)
Reason: The gray code of 1001 is 1101
|
Answer : (d)
Reason: Unsigned binary representation occupies less space to store the number +255.
| |
Answer : (c)
Reason: The AND, and OR functions are only two of a total of 16 possible functions formed with two binary variables. Therefore, for two variables n=2, and the number of possible Boolean functions is 16.
| |
Answer : (b)
Reason: This means that it is not practical for use in systems requiring high-speed operations. The characteristic parameters for the CMOS gate depend on the power supply voltage VDD that is used. The power dissipation increases with increase in voltage supply. The propagation delay decreases with increase in voltage supply and the noise margin is estimated to be about 40% of the voltage supply value.
| |
Answer : (a)
Reason: Consider the 20-bit logical address. The 4-bit segment number specifies one of 16 possible segments. The 8-bit page number can specify up to 256 pages, and the 8-bit word field implies a page size of 256 words. This configuration allows each segment to have any number of pages up to 256. the smallest possible segment will have one page of 256 words. The largest possible segment will have 256 pages, for a total of 256*256 = 65,536 which means 64K words.
| |
Answer : (b)
Reason: Associative memories are expensive compared to random-access memories because of the added logic associated with each cell. Therefore, the simplest way to determine cache locations in which to store memory blocks is the Direct Mapping.
| |
Answer : (d)
Reason: 2’s complement of -6 = 11111010
2’s complement of -13 = 11110011
Add the two numbers in their 2’s complement form, including their sign bits and discard any carry out of the sign (leftmost) bit position. So the answer is 11101101 (-19).
-6 11111010
-13 11110011
------------------
-19 11101101
| |
Answer : (e)
Reason: Program Counter (PC) keeps track of the instruction of the program stored in memory.
| |
Answer : (a)
Reason: The major components of CPU are Control Unit, Register Set, and Arithmetic Logic Unit.
| |
Answer : (d)
Reason:
|
Cool you write, the information is very good and interesting, I'll give you a link to my site.
ReplyDeleteBios Chip Acer
It has been simply incredibly generous with you to provide openly what exactly many individuals would’ve marketed for an eBook to end up making some cash for their end, primarily given that you could have tried it in the event you wanted.
ReplyDeleteAWS Training in Bangalore